Hello,

I need you guys understanding indirect indexed addressing. In the following suppose that "backg" is the label of where some name table data is included.

lda #low(backg)
sta $10
lda #high(backg)
sta $11

ldx #4
ldy #0
loop:
lda [$10],y
sta $2007
iny
bne loop
inc $11 ; This is what i don't understand
dex
bne loop

I understand that this is loading 4 chunks of 256 bytes. But the instruction i don't get is the inc $11. I know that this increments the high byte address of the data to the next 256 bytes chunk. But let's say that the address of "backg" is $82C5. When incrementing the high byte of the address, does it becomes $82C6? If yes then it's not a step of 256 bytes! If no then, what is the address after it's incremented?

It is incrementing the high byte, but remember that the on the 6502 the low byte is first.

So $10 is the low byte (no need to change it since Y covers that area), and $11 is the high byte, and when it's incremented the next address would be $83C5.

Which makes the step of 256 bytes. I'm still confused about something though.

The low byte of $82C5 is $82, and the high byte is $C5, right? So why when incrementing $C5, it affects $82 so that it becomes $83C5? Does it means that i should increment the low byte to get $82C6?

It's doing like the opposite i thought.

> The low byte of $82C5 is $82, and the high byte is $C5, right

Other way around. The "high" byte is the most significant byte

$XXxx

XX = high byte
xx = low byte

Ohhhh, suddently everything is clear. Thanks!