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SubjectAgain $2005 ....  
Posted byIndy
Posted on12/29/01 9:42 PM
From IP62.40.201.139  



Hi all!

I'm a bit confused with loopy's 2005 doc:

The first line is completely clear to me
2000 write:
t:0000110000000000=d:00000011
d is written to $2000 (use nametable 3) so the adress in the temp adress value is $C00 (offset of the 3rd nametable).

But now - line 2 confuses me completely:
2005 first write:
t:0000000000011111=d:11111000
x=d:00000111

I suppose that d is written to $2000 again (or is that maybe wrong??). If it's true the nametable adress is now $2000 (or 0000 in the t). So why is the 11111 there? If I'm wrong and d is written to $2005 i don't understand why the 11111 is in t either. (it looks like the bits in d are mirrored and transfered to t).

Hope somebody can help me out of this -):)

Regards Martin




-
Entire Thread
Subject  Posted byPosted On
.Again $2005 ....  Indy12/29/01 9:42 PM
.*Re: Again $2005 ....  teaguecl1/2/02 03:48 AM
..*Re: Again $2005 ....  Indy1/2/02 2:31 PM
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