|
Hi all!
I'm a bit confused with loopy's 2005 doc:
The first line is completely clear to me 2000 write: t:0000110000000000=d:00000011 d is written to $2000 (use nametable 3) so the adress in the temp adress value is $C00 (offset of the 3rd nametable).
But now - line 2 confuses me completely: 2005 first write: t:0000000000011111=d:11111000 x=d:00000111
I suppose that d is written to $2000 again (or is that maybe wrong??). If it's true the nametable adress is now $2000 (or 0000 in the t). So why is the 11111 there? If I'm wrong and d is written to $2005 i don't understand why the 11111 is in t either. (it looks like the bits in d are mirrored and transfered to t).
Hope somebody can help me out of this -):)
Regards Martin
|